Find the class marks of 10 – 25 and 35 – 55

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WebJul 9, 2024 · Find the mean, median and mode of the following data: Marks obtained 25 - 35,35 - 45,45 - 55,55 - 65,65 - 75, 75 - 85 asked Jul 9, 2024 in Statistics by Ankush01 ( … Web(a) 45 (b) 25 (c) 35 (d) 40 Ans : (c) 35 Lower class limit = Upper class limit - width of class 60 5- =55 continuous classes in a frequency distribution is 35-40, 40-45, 45-50, 50-55, 55-60 Lower class limit of lowest class is 35. 8. The class marks of a frequency distribution are 15, 20, 25, 30, ..... The class corresponding to the class mark ...

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WebLet x 1, x 2, x 3,…,x n are mid-points or class marks of n class intervals and f 1, f 2, f 3, …, f n are the respective frequencies. The formula of the assumed mean method is: Here, a = assumed mean. f i = frequency of ith class. ... 15-25: 2: 25-35: 4: 35-45: 4: 45-55: 7: 55-65: 11: 65-75: 6: Find the mean percentage of female employees by ... WebApr 19, 2024 · Find the class marks of classes 10-25 and 35-55. 6,649 views Apr 18, 2024 132 Dislike Share Save Doubtnut 2.25M subscribers Find the class marks of classes 10 … staying at ravenseat farm

Find the class marks of classes 10-25 and 35-55. - YouTube

WebClass mark of 10 - 25 = upper limit - lower limit 2 = 25 + 10 2 = 35 2 = 17. 5 So, class marks of class 10 - 25 is 17. 5 Class mark of 35 - 55 = upper limit - lower limit 2 = 55 + … WebSOLUTION. Class Mark = Upper Limit+Lower Limit2. Class Mark of 10-25 = 25+102= 352= 17.5. Class mark of 35-55 = 35+552= 902= 45. Related Questions. The following table … WebThe class marks are uniformly spread. The class size is the difference between anty two consecutive class marks. Class size = 25 - 15 = 10 The lower limit of the first class = … staying at fort wilderness cabin

Find the class marks of classes 10 -25 and 35 – 55.

WebFind the class marks of classes 10 -25 and 35 – 55. mean mode median class-10 1 Answer +1 vote answered Sep 10, 2024 by AmirMustafa (60.4k points) selected Sep 23, 2024 by Vikash Kumar Best answer Class … WebMay 7, 2024 · Question. Find the class-marks of the classes 10-25 and 35-55. Solution. Class-mark of class 10 – 25 = 10 + 25/2 = 35/2 = 17.5 Class-mark of class 35–55 = 35 + 55/2 = 90/2 = 45. Question. The mileage (km per litre) of 50 cars of the same model was tested by a manufacturer and details are as follows: Find the mean mileage. staying at the most scary hotelWebFind the class marks of classes 10 -25 and 35 – 55. Find the class marks of classes 10 -25 and 35 – 55. CBSE Class 10 Statistics. Find the class marks of classes 10 -25 and 35 – 55. Search for: i. More Material. Write chromyl chloride test with equation. What do you understand by lanthanide contraction. staying at portmeirion village

"WebA school has four section of chemistry in class XII having 40, 35, 45 and 42 students. The mean marks obtained in Chemistry test are 50, 60, 55 and 45 asked Feb 25, 2024 in Statistics by RonitBhatt ( 19.3k points) " - Find the class marks of 10 – 25 and 35 – 55

Find the class marks of 10 – 25 and 35 – 55

Find the Class Marks of Classes 10 -25 and 35 – 55. - Mathematics

WebAbout Press Copyright Contact us Creators Advertise Developers Terms Privacy Policy & Safety How YouTube works Test new features Press Copyright Contact us Creators ... WebThe cumulative frequency just greater than 50 is 71 and the corresponding class is 45 – 55. Thus, the median class is 45 – 55. ∴ l = 45, h = 10, N = 100, f = 33 and cf = 38. Now, Median = l +`((N/2- cf)/f) xxh` `=45+((50-38)/33) xx 10` = 45 + 3.64 = 48.64 Thus, the median is 48.64. We know that, Mode = 3(median) – 2(mean) = 3 × 48.64 ...

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WebFor the class 55 - 59, The actual lower limit = 55 - 0.5 = 54.5 The actual upper limit = 59 + 0.5 = 59.5 ∴ The class boundaries are 54.5 and 59.5. ∴ The class mark = `(1)/(2)(54.5 + 59.5)` = 57. Similarly calculating for the other classes we get the following table: WebJun 10, 2010 · Find the class marks of classes 10 - 25 and 35 - 55. Share with your friends 6 Follow 1 Nitin Gupta, added an answer, on 11/6/10 Class Mark = Upper Limit + Lower …

WebFind the class marks of classes 10 - 25 and 35 - 55. 8 While calculating the mean of a given data by the Assumed - mean method, the following values were obtained: A = 25, … Web(a) What is the lower limit of fourth class interval? (b) What is the class size of each class interval? (c ) Which class interval has the highest frequency? (d) Find the class marks of all the class intervals? 9. Construct the frequency distribution table for the data on heights (cm) of 20 boys using the class intervals 130 - 135, 135 - 140 ...

Webe) Lower limit is 35 and upper limit is 46 f) The class mark is 5. Find the actual lower class limits, upper class limits and the mid-values of the classes: 10-19, 20-29, 30-39 and 40-49. Solution: Case 1: frequency 10 – 19, The lower class limit is 10 The upper class limit is 20 Mid-value is, Case 2: frequency 20 - 29 Web10. Find the class marks of classes 10 - 25 and 35 - 55. ai 10-25 747 35-65 af faa 1 Solution Verified by Toppr Was this answer helpful? 0 0 Similar questions Divide 64 into …

WebQ. Nos. 16 to 20 are short answer type questions of 1 mark each. 16. If sin A + sin2 A = 1, then find the value of the expression (cos2 A + cos4 A). Ans: 2 2 sinA 1 sin A sinA cos A =− ⎫ ⎬ = ⎭ 1/2 cos2A + cos4 A = sin A + sin2 A = 1 1/2 17. In Fig. 4 is a sector of circle of radius 10.5 cm. Find the perimeter of the sector. 22 Takeπ 7 ...

WebJan 22, 2024 · The relationship between mean, median and mode for a moderately skewed distribution is. If the mode of the following distribution is 57.5, find the value of ' x '. Find … staying at the clown motelWebStep 1: Calculate the class marks of each class (x i). Step 2: Let A denote the assumed mean of the data. Step 3: Find u i = (x i −A)/h, where h is the class size. Step 4: Use the formula: x̄ = A + h × (∑f i u i /∑f i) Example: Consider the following example to understand this method. Find the arithmetic mean of the following using the ... staying at ronald mcdonald houseWebFeb 25, 2024 · Find the class mark of classes 10-25 and 35-55. OR Find the value of x, if the mode of the following data is 25. 15, 20, 25, 18, 14, 15, 25, 15, 18, 16, 20, 25, 20, x, 18 Solution : 17.5,45 OR 25. Question 15. … staying at the rocks sydneyWebApr 2, 2024 · We have to find the class mark of the class interval 50-60. ... = 55 \\ $ Hence, the class mark of the interval 50-60 is 55. Note: The average of the class limits of an interval is called a class mark or mid-value of the interval. Class marks are also known as the central value of the interval. It helps in calculation of mean and median. staying awake until your scheduled bedtimeWebFind the class marks of classes 10 — 25 and 35 — 55. 10-25 I 30/2/1 . SECTION B Questions number 11 to 15 carry 2 marks each. 11 à 15 2 1 Il. Find all the zeros of the polynomial x4 + x ... 25 and 35 -55. 10-25 35-55 I Complete the missing entries in the following factor tree : If (x + a) is a factor of 2x2 + 2ax + 5x + 10, find a. staying at the reform club londonWebDec 4, 2024 · Find the class marks of class 10 − 25 and 35 − 55: [Board Question] (a) 1.75 and 45 (b) 17.5 and 4.5 (c) 1.75 and 4.5 (d) 17.5 and 45 Updated On Dec 4, 2024 staying at isle of wightWebTo calculate this, we first sum up the two marks and then apply the equation as usual: (92 + 88) / 200 x 100 = 180 / 200 x 100 = 0.90 x 100 = 90% so the overall percentage mark is 90%. The table below shows the test grades on a given examination and their corresponding percentages assuming a maximum mark of 200. Mark percentages with a maximum ... staying awake in class